25k^2+12=35k

Solution for 25k^2+12=35k equation:

25k^2+12=35k

We move all terms to the left:

25k^2+12-(35k)=0

a = 25; b = -35; c = +12;
Δ = b2-4ac
Δ = -352-4·25·12
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-5}{2*25}=\frac{30}{50}
=3/5
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+5}{2*25}=\frac{40}{50}
=4/5
$